Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A stone of mass m is tied to a string and is moved in a vertical circle of radius r making n revolutions per minute . The total tension in the string when the stone is at its lowest point is
Text Solution
Verified by ExpertsThe correct answer is:
D
\(\tau = mg + m \omega^2 r = m (g + 4 \pi^2 n^2 r)\)
\(=m\left|g+\left|4\pi^2\frac{r}{60^2}r\right|\right|=m\left|g+\left|\frac{7.7^2\pi^2r}{900}\right|\right|\)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A body of mass \(\pi\pi\) hangs at one end of a string of length l , the other end of which is fixe…
The tension in the string revolving in a vertical circle with a mass m at the end which is at the l…
A stone of mass m is tied to a string and is moved in a vertical circle of radius r making n revolu…
A tube of length l is filled completely with an incompressible liquid of mass \(\mathbf{M}\) and cl…
The kinetic energy k of a particle moving along a circle of radius R depends on the distance covere…
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/sec . A…